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4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Sun Dec 28, 2014 2:11 pm
by BAA
Mike-SE,

Your commentary states that: "You cannot determine the S for this member directly (try to if you don't believe me.)"

Although, I can arrive at the answer given in NCARB and follow the logic you prescribed for solving for I, I don't understand why this same logic cannot be applied to solving for S directly. Once b is known, and d is known, why will it not produce the same/correct answer?

Here is the logic:

1. For solid rectangle. S = b x d (squared) /6 = 6 x 10 (squared)/ 6 = 6 x 100 / 6 = 600/6 = 100
2. For the side rectangles. S = b x d (squared) / 6 = 2.5 x 8 (squared) / 6 = 2.5 x 64 /6 = 160 / 6 = 26.667
3. Multiple by 2 to account for both sides. 2 x 26.667 = 53.333
4. Subtract solid rectangle from side rectangles. 100 - 53.333 = 46.667

If the process works for the Moment of (I)nertia , why does it not work for the (S)ection Modulus? The b's and d's are known, why can they not be applied? Why do we have to go through I to get S, if S = bd^2 /6 and/or S = I/C ?

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Mon Dec 29, 2014 7:55 am
by Mike-SE
you math is correct. BUT the correct answer is 57.33 in^3 Your method came up with a wrong answer

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Mon Dec 29, 2014 9:03 am
by BAA
Mike-SE wrote:you math is correct. BUT the correct answer is 57.33 in^3 Your method came up with a wrong answer



Is there any rule to know which and when to apply a certain method? I feel like I'm missing something very fundamental.

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Mon Dec 29, 2014 10:02 am
by Mike-SE
ALWAYS calculate the moment of inertia

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Tue Dec 30, 2014 2:51 pm
by BAA
Found a great explanation for this. See:

http://www.dustingoffron.com/ARE/NCARB3.pdf


Parallel Axis Theorem

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Thu Apr 16, 2015 8:05 pm
by cam
Thank you BAA, that explanation was extremely helpful!! I was stumped! :D

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Sat Apr 18, 2015 9:55 pm
by 14Finish
When calculating the moment of inertia I am double guessing which dimension should be d and thus be cubed. In ballast I think I read that d is always perpendicular to the axis. No primary axis is given in this example. How would you know to pick the X-X axis? I get a completely different answer when I try to calculate it through the Y-Y axis.

How would your process change if an axis is shown in the diagram vs. not shown?

I test Monday. Any help is much appreciated! Thanks!!

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Sun Apr 19, 2015 9:19 am
by SoonArch
14Finish,

I was confused too. Finally I realized the diagram is given in section, and you can assume the B for BASE is the bottom plane, the one that is "grounded". Does this make sense?

If there is no diagram, they would have to tell you in text. There is no other way.

Re: 4.0 NCARB QUES. No. 6 - Section Modulus Process?

PostPosted: Sun Apr 19, 2015 1:08 pm
by 14Finish
Thanks SoonArch! That is very helpful.

All the guides emphasized the direction of the axis so I thought I must be missing something.